Question

How do you find the derivative of `(t^3+1)^100` using the chain rule?

Answer 1

`300t^2(t^3+1)^99`

Explanation:

According to the chain rule:

`d/dx[(t^3+1)^100]=100(t^3+1)^99*d/dx[t^3+1]`

`=100(t^3+1)^99*3t^2`

`=300t^2(t^3+1)^99`