How do you solve #2- 7 - log _ 3 8x = 2#?

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Answer 1 · 2015-11-24T15:58:57

#x=1/17496#

#2-7-log_3 8x=2#

#-5-log_3 8x=2#

#-log_3 8x=7#

#log_3 8x=-7#

#3^(log_3 8x)=3^-7#

#8x=1/2187#

#x=1/17496#