Question

How do you differentiate `f(x)=sinsqrtx` using the chain rule?

Answer 1

`f'(x)=(cossqrtx)/(2sqrtx)`

Explanation:

According to the Chain Rule:

`f'(x)=cossqrtx*overbrace(d/dx[sqrtx])^(d/dx[x^(1/2)])`

`f'(x)=cossqrtx*1/2x^(-1/2)`

`f'(x)=(cossqrtx)/(2sqrtx)`