Question

How do you solve `2 Log (x - 4) = 4 log 2`?

Answer 1

We must have `x-4>0=>x>4` hence

`2log(x-4)=4log2=>log(x-4)^2=log2^4=>(x-4)^2=2^4=>x-4=+-4=>x=8 or x=0`

Finally `x=8`