Question

How do you find the inverse of `y=(4x+2)/(x-7)`?

Answer 1

`x=(7y+2)/(y-4)`

Explanation:

You must isolate `x` in terms of `y`: multiply both sides by `x-7`:

`(x-7)y = 4x+2`

`xy-7y = 4x+2`

`xy-4x=7y+2`

`x(y-4)=7y+2`

`x=(7y+2)/(y-4)`