Question

How do you solve `-4(5^x)=-68`?

Answer 1

I found: `x=1.76037`

Explanation:

We can start rearranging our expression:
`5^x=(-68)/(-4)`

`5^x=17`

take the natural log of both sides:

`ln5^x=ln17`

use the property of logs: `logx^a=alogx`:
so:
`xln5=ln17`
so:
`x=ln(17)/ln(5)=1.76037`