Question

How do you solve `log_3 x=5log_10 2`?

Answer 1

`x=3^(log_10 32)`

Explanation:

Rewrite as:

`log_3x=log_10 (2^5)`

`log_3x=log_10 32`

`3^(log_3x)=3^(log_10 32)`

`x=3^(log_10 32)`

`x~~5.226`