How do you factor the trinomial d^2 + 15d + 44?

2 Answers
Dec 2, 2015

d^2+15d+44=(x+4)(x+11).

Explanation:

d^2+15d+44

Find two numbers that when added equal 15 and when multiplied equal 44. The numbers 4 and 11 meet the criteria.

Rewrite the trinomial as (x+4)(x+11).

Dec 2, 2015

(d+11)(d+4),
d=-11,
d=-4.

Explanation:

You multiply the constant multiplying d, which is 1, times the last number, 44. This gives us the value 44. Now you look for factors of 44 that add up to 15. These are 11 and 4. So, we write them in the form (d+a)(d+b), where d is d, a is the first factor, 11, and b is the second factor, 4. So,
(d+11)(d+4) = 0
d=-11,
d=-4.

Hope it Helps! :D .