How do you factor the expression #x^2 - x - 6#?

1 Answer
Dec 3, 2015

#x^2 - x - 6 = (x - 3)(x + 2)#

Explanation:

There are many possible ways to gain the factorisation. Let me show you one of them.

You would like to have something like

#x ^2 - x - 6 = (x + a)(x + b)#
#color(white)(xxxxxxxii) = x^2 + (a+b)x + a*b#

So, your goal is to determine #a# and #b# so that

#{ (a + b = -1), ( color(white)(x) a * b = -6) :}#

hold.

This approach is not always possible or can be complicated if your solutions are not integers.
Here, however, it's one of the easiest ways to compute the result. :-)

You know that # a * b = -6# can be achieved either with # -3 * 2 = -6# or with #3 * (-2) = -6#.

Let's test which pair works for the first equation:
#-3 + 2 = -1# works perfectly well, so it's #a = -3# and #b = 2#.

Thus, your factorization is:

#x^2 - x - 6 = (x - 3)(x + 2)#.