How do you simplify $\frac{1}{2} (3 + 4^{2})$ $1/2( 3 + 4^2)$ using order of operations?

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Answer 1 · 2015-12-03T12:27:00

$\frac{1}{2} (3 + 4^{2}) = \frac{19}{2}$ $1/2(3+4^2)=19/2$

$\frac{1}{2} (3 + 4^{2}) = \frac{1}{2} (3 + 16)$ $1/2(3+4^2)=1/2(3+16)$
$= \frac{1}{2} \cdot 19$ $=1/2*19$
$= \frac{19}{2}$ $=19/2$

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