How do you factor the trinomial #x^2 - 16 #?

2 Answers
Dec 3, 2015

#(x+4)(x-4)#.

Explanation:

We use #(a+b)(a-b)# for this type of operation. To do this, we have to find the way to put numbers squared. #x# is already squared, but #16# has to be put as #4^2#. Now, #a = x# and #b = 4#. So, we substitute:
#(x+4)(x-4)#.

Hope it Helps! :D .

Dec 3, 2015

Apply the difference of squares formula to find that
#x^2 - 16= (x+4)(x-4)#

Explanation:

The difference of squares formula states that
#a^2 - b^2 = (a+b)(a-b)#
(try multiplying the right side out to verify this)

As #16 = 4^2# we have

#x^2 - 16 = x^2 - 4^2 = (x+4)(x-4)#