How do you convert #y = sqrt(3)x# into polar form?

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Answer 1 · 2015-12-04T16:54:19

Use these identities ...
#x=rcostheta#
#y=rsintheta#

Using substitution , insert the identities above into the equation:

#rsintheta=sqrt3xxrcostheta#

#r(sintheta -sqrt3costheta)=0#

#sintheta=sqrt3costheta#

#tantheta=sqrt3#

#theta=pi/3#

So, polar form is a straight line : #theta = pi/3#

hope that helped