Question

How do you simplify `cot(x-2y)` to trigonometric functions of x and y?

Answer 1

`cot(x-2y) = cos(x-2y)/sin(x-2y)`

Explanation:

Just by applying definitions, you have that

`cot(theta)=1/tan(theta)=1/(sin(theta)/cos(theta))=cos(theta)/sin(theta)`

So, you have that

`cot(x-2y) = cos(x-2y)/sin(x-2y)`

which I'd say it's ok because it's an expression involving only trigonometric functions (`cos` and `sin`) of `x` and `y`.