Question

Consider two vectors A=3i - 1j and B = - i - 5j, how do you calculate `abs(A-B)`?

Answer 1

`|A-B|=sqrt32`

Explanation:

`A-B= A+(-B)`

`=3 hati-hatj+(hati+5hatj)`

`=4hati-4hatj`

`therefore|A-B|=|4hati-4hatj|`

`=sqrt(4^2+4^2)`

`=sqrt32`