How do you differentiate #y = -1/(1+x^2)# using the quotient rule?

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Answer 1 · 2015-12-11T00:38:56

#y'=(2x)/(1+x^2)^2#

According to the quotient rule:

#y'=-((1+x^2)d/dx[1]-1d/dx[1+x^2])/(1+x^2)^2#

Find each derivative.

#d/dx[1]=0#

#d/dx[1+x^2]=2x#

Plug both back in.

#y'=-((1+x^2)(0)-1(2x))/(1+x^2)^2#

#y'=(2x)/(1+x^2)^2#