How do you solve # 2a^(t/3)=5#?

1 Answer
sente
Dec 13, 2015

Use a logarithm to remove #t# from the exponent and find that
#t = (3ln(5/2))/ln(a)#

Explanation:

Using the property of logarithms that
#ln(a^x) = xln(a)#
we have

#2a^(t/3) = 5#

#=> a^(t/3) = 5/2#

#=> ln(a^(t/3)) = ln(5/2)#

#=> t/3ln(a) = ln(5/2)#

#=> t = (3ln(5/2))/ln(a)#

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