Question

Question #bafc0

Answer 1

`0,0017mol`

Explanation:

Since concentration is moles per unit volume (`c=n/V`), and moles is mass over molar mass (`n=m/(M_r`), we may combine the two to obtain that

`c=m/(M_r*V)`

`therefore m=c*M_r*V`

`=2,28mol//dm^3xx(39+80)g//molxx0,00075dm^3`

`=0,2035g`.

This corresponds to the following number of moles :

`n=m/(M_r)=(0,2035g)/(119g//mol)=0,0017mol`.