How do you solve x^2-3x-10=0? Algebra Quadratic Equations and Functions Comparing Methods for Solving Quadratics 1 Answer Özgür Özer Dec 15, 2015 "Solution Set"={5,-2} Explanation: color(white)(xx)x^2-3x-10=(x-5)(x+2) For x-5=0, =>color(red)(x_1=5) For x+2=0, =>color(red)(x_2=-2) "Solution Set"={5,-2} Answer link Related questions What are the different methods for solving quadratic equations? What would be the best method to solve -3x^2+12x+1=0? How do you solve -4x^2+4x=9? What are the two numbers if the product of two consecutive integers is 72? Which method do you use to solve the quadratic equation 81x^2+1=0? How do you solve -4x^2+4000x=0? How do you solve for x in x^2-6x+4=0? How do you solve x^2-6x-16=0 by factoring? How do you solve by factoring and using the principle of zero products x^2 + 7x + 6 = 0? How do you solve x^2=2x? See all questions in Comparing Methods for Solving Quadratics Impact of this question 1388 views around the world You can reuse this answer Creative Commons License