How do I find the derivative of #ln (6^s)#?

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Answer 1 · 2015-12-15T09:37:57

#ln(6)#

Here, there is a very easy way to solve the problem.

Use the logarithmic law

#ln (a^r) = r * ln(a)#

Thus, your function can be transformed into

#ln(6^s) = s * ln(6)#

As #ln(6)# is just a constant, the derivative is easy:

#d/(ds) ln(6) s = ln(6)#