Question

How do you write the equation of the circle in standard form `x^2+y^2-6x+4y-3+0`?

Answer 1

`(x - 3)^2 + (y + 2)^2 = 4^2`

Explanation:

`(x^2 - 2 * 3 *x + 3^2) - 3^2 +`

`+ (y^2 + 2 * 2 * y + 2^2) - 2^2 - 3 = 0`

`Rightarrow (x - 3)^2 + (y + 2)^2 = 9 + 4 + 3`