How do you divide (x^3 − 3x^2 + 7x + 2) (x3−3x2+7x+2) by x-1x−1?

1 Answer
Topscooter
Dec 17, 2015

The answer will be : x^3 - 3x^2 + 7x + 2 = (x-1)(x^2 - 2x - 5) + 7x3−3x2+7x+2=(x−1)(x2−2x−5)+7

Explanation:

You basically divide x^3 - 3x^2 + 7x + 2x3−3x2+7x+2 by x-1x−1 by using the euclidean method, just like you would do it if you were dividing a natural number a by another number b : you will here try to delete the 3rd degree terms, then the 2nd degree terms, then the 1st degree terms.

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