Question #8440d

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Answer 1 · 2015-12-17T22:54:42

#174˚"C"#

What you're most likely forgetting is that temperature must be converted to the Kelvin scale.

To convert from Celsius to Kelvin, add #273#.

Charles's Law states that

#("V"_1)/("T"_1)=("V"_2)/("T"_2)#

so,

#(2.00"L")/(25.0+273"K")=(3.00"L")/("T"_2)#

#"T"_2=447"K"#

To convert back to Celsius, subtract #273#.

Your final answer is #174˚"C"#.