Question

If an object is moving at `1 m/s` and accelerates to `12 m/s` over 3 seconds, what was the object's rate of acceleration?

Answer 1

`a~~4"m/s"^2"`

Explanation:

`a=(v_f-v_i)/(Delta t)`, where `v_f="12 m/s"`, `v_i="1 m/s"`, `Delta t="3 s"`.

`a=(12"m/s"-1"m/s")/(3"s")`

`a=(11"m/s")/(3"s")=11/3 "m/s"^2~~"4 m/s"^2"` (rounded to one significant figure)