Question

How do you solve `(y+2)/y=1/(y-5)`?

Answer 1

`y = 2 +sqrt(14)`

Explanation:

First multiply out to get rid of denominators:
`(y+2)(y-5) = 1*y`
`y^2 -3y - 10 -y = 0`
`y^2 - 4y - 10 = 0`
Using completing the squares
`(y - 2)^2 - 10 - 4 = 0`
`(y-2)^2 =14`
`y = 2 +sqrt(14)`