Question

How do you solve `3 log x=1.5`?

Answer 1

`x=sqrt(10)`

Explanation:

`3log(x) = log(x^3)`

`10^(log(x^3)) = x^3`

So if `3log(x) = 1.5`
then
`color(white)("XXX")x^3= 10^(1.5) = 10^(0.5)xx10^(0.5)xx10^(05)`

`color(white)("XXX")rarr x= 10^(0.5) = sqrt(10)`