Question

What is the force, in terms of Coulomb's constant, between two electrical charges of `-25 C` and `60 C` that are `15 m` apart?

Answer 1

`6.667k` newtons

Explanation:

Coulomb's Law states that the electrostatic force between 2 point charges is directly proportional to the product of the 2 charges and inversely proportional to the square of the distance between them.
ie. `F=k(Q_1Q_2)/r^2`,
where `k=9xx10^9N.m^2//kg^2` is Coulomb's Constant.

So, in terms of Coulomb's constant, this particular force will be

`F=k(25xx60)/(15^2)`

`=6.667k` newtons

Note also that this force will be attraction since it is unlike charges.