How do you factor the expression #c^2 + 4c + 4#? Algebra Polynomials and Factoring Factorization of Quadratic Expressions 1 Answer Alan P. Dec 24, 2015 #c^2+4x+4=color(green)((c+2)(c+2))# Explanation: Since #(c+m)(c+n)=c^2+(m+n)c+mn# we are looking for factors (#m# and #n#) of #4# which add up to #4# Factors of #4# #color(white)("XXX")1xx4# but #1+4!=4# #color(white)("XXX")2xx2# and #2xx2=4# Hooray! we've found our pair. Answer link Related questions How do you factor trinomials? What is factorization of quadratic expressions? How do you factor quadratic equations with a coefficient? What are some examples of factoring quadratic expressions? How do you check that you factored a quadratic correctly? How do you factor #x^2+16x+48#? How do you factor #x^2-9x+20#? Question #3fdac How do you factor #8+z^6#? There is no GCF to be factor out, so is there another method to complete this? How do you factor #2t^2+7t+3#? See all questions in Factorization of Quadratic Expressions Impact of this question 2834 views around the world You can reuse this answer Creative Commons License