How to find the asymptotes of f(x) = (x^2-1)/(2x^2 + 3x-2)f(x)=x212x2+3x2?

1 Answer
Dec 25, 2015

-2 and -1/2 are the asymptotes

Explanation:

To find the asymptotes of an equation, think of values that cannot be a result of the function when it is substituted by many values.

In this case, since it is a fraction, 0 denominator is not possible cpbecause it will lead to undefine , so to find the asymptotes, find values that could make the denominator.

So let 2x^2 + 3x -2=02x2+3x2=0

Then solve for x

2x^2 + 3x -2=02x2+3x2=0
(2x-1)(x+2)=0(2x1)(x+2)=0
2x-1=02x1=0
x=1/2x=12
And

x+2=0x+2=0
x=-2x=2

So the asymptotes are -2 and 1/212