Question

How do you solve `log _2 x – log_2 4 = 2`?

Answer 1

I found: `x=16`

Explanation:

You can use the property of logs that says:
`logx-logy=log(x/y)`
and get:
`log_2(x/4)=2`
use the definition of log to change it into an exponential and get:
`x/4=2^2`
`x=4*4=16`