How do you differentiate #f(x)= x/sqrt(1-x^2) # using the quotient rule?
1 Answer
Dec 30, 2015
We can see this as a product:
Explanation:
- Chain rule states that for
#y=f(x)g(x)# , then#(dy)/(dx)=f'(x)g(x)+f(x)g'(x)# - Chain rule states that
#(dy)/(dx)=(dy)/(du)(du)/(dx)#
Renaming