How do you factor the trinomial x^2 + 4x - 32 ?

1 Answer
Dec 30, 2015

You find its roots then write them in factor form, which means equaling each root to zero.

Explanation:

Solving using Bhaskara:

(-4+-sqrt(4^2-4(1(-32))))/2

(-4+-sqrt(16+128))/2

(-4+-sqrt(144))/2

(-4+-12)/2

x_1=4 => Factor form: x-4=0
x_2=-8 => Factor form: x+8=0

Thus, x^2+4x-32=color(green)((x-4)(x+8))