How do you differentiate #f(x)=e^(x^3-x^2-4) # using the chain rule? Calculus Basic Differentiation Rules Chain Rule 1 Answer GiĆ³ Jan 1, 2016 I found: #y=(3x^2-2x)e^(x^3-x^2-4)# Explanation: First you derive #e# alone as it is and then multiply by the derivative of the exponent (in red): #y=e^(x^3-x^2-4)*[color(red)(3x^2-2x)]# Answer link Related questions What is the Chain Rule for derivatives? How do you find the derivative of #y= 6cos(x^2)# ? How do you find the derivative of #y=6 cos(x^3+3)# ? How do you find the derivative of #y=e^(x^2)# ? How do you find the derivative of #y=ln(sin(x))# ? How do you find the derivative of #y=ln(e^x+3)# ? How do you find the derivative of #y=tan(5x)# ? How do you find the derivative of #y= (4x-x^2)^10# ? How do you find the derivative of #y= (x^2+3x+5)^(1/4)# ? How do you find the derivative of #y= ((1+x)/(1-x))^3# ? See all questions in Chain Rule Impact of this question 1390 views around the world You can reuse this answer Creative Commons License