Question

What is the instantaneous rate of change for `g(x) = x^2 − x + 4` when x=-7?

Answer 1

`-15`

Explanation:

Find `g'(-7)`.

Use the power rule: `d/dx(x^n)=nx^(n-1)`

`g'(x)=2x^(2-1)-1x^(1-1)+0(4x^(0-1))`

`g'(x)=2x-1`

Again, find the instantaneous rate of change by computing `g'(-7)`.

`g'(-7)=2(-7)-1=-14-1=-15`