Question

How do you write the equation of the circle with the given center and radius: Center at (3, -6); radius = 5?

Answer 1

You can use the general telationship:
`(x-h)^2+(y-k)^2=r^2`

Explanation:

In the above relationship `(h,k)` are the coordinates of the center while `r` is the radius of your circle.
You should get:

`(x-3)^2+(y+6)^2=5^2`

Try to expand this equation by yourself to get to the equation of the circle in the form:
`x^2+y^2+....=0`