Question

How do you find the equation of the circle, given the center and radius (0,0);4?

Answer 1

The equation of the circle would be `x^2+y^2=16`

Explanation:

The general equation of a circle is:
`(x-a)^2+(y-b)^2=r^2`
where `a` is the `x` coordinate of the center, `b` is the `y` coordinate of the center, and `r` is the radius of the circle.

Applying this to your conditions, we get:
`(x-0)^2+(y-0)^2=4^2`

which is

`x^2+y^2=16`