Question

How much energy is absorbed as heat by 21 g of gold when it is heated from 25°C to 35°C?

Answer 1

`q=27.09 J`

Explanation:

The amount of heat absorbed by the system could be calculated by:

`q=mxxsxxDeltaT`

where,
`q` is the heat,
`m` is the mass of the gold sample,
`s=0.129 J/(g*^@C)` is the specific heat capacity of gold
and `DeltaT=T_f-T_i=35^@-25^@=10^@C` is the change on temperature of the sample.

`=>q=21cancel(g)xx0.129 J/(cancel(g)*cancel(""^@C))xx10cancel(""^@C)=27.09 J`

Here is a video that explains more about this topic:
Thermochemistry | Enthalpy and Calorimetry.