Question

How do you solve the rational equation `(x-3)/(x+1)=(x-6)/(x+5)`?

Answer 1

I found: `x=9/7`

Explanation:

I would get rid of the denominators changing side and multiplying:
`(x-3)(x+5)=(x-6)(x+1)`
`cancel(x^2)+5x-3x-15=cancel(x^2)+x-6x-6`
`2x-15=-5x-6`
`7x=9`
`x=9/7`