How do you write the standard form of the equation of the circle with the given the center (-3,1) and radius of 7?

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Answer 1 · 2016-01-05T00:07:22

#(x+3)^2+(y-1)^2=49#

#(x-h)^2+(y-k)^2=r^2#

Where the center is #(h,k)# and the radius is #r#.

Thus,

#h=-3#
#k=1#
#r=7#

Plug these in to the standard form:

#(x-(-3))^2+(y-1)^2=7^2#

When simplified:

#(x+3)^2+(y-1)^2=49#