How do you solve #5/(2x) - 1/12 = 3/x#? Algebra Rational Equations and Functions Clearing Denominators in Rational Equations 1 Answer Don't Memorise Jan 5, 2016 #color(blue)(x =-6# Explanation: #5/(2x) -1/12 = 3/x# #5/(2x) - 3/x=1/12# #5/(2x) - (3xx2)/(x xx 2)=1/12# #5/(2x) - 6/(2x)=1/12# #- 1/(2x)=1/12# #- 1 xx 12 =2x# #- 12 =2x# #- 12/2 =x# #color(blue)(x =-6# Answer link Related questions What is Clearing Denominators in Rational Equations? How do you solve rational expressions by multiplying by the least common multiple? How do you solve #5x-\frac{1}{x}=4#? How do you solve #-3 + \frac{1}{x+1}=\frac{2}{x}# by finding the least common multiple? What is the least common multiple for #\frac{x}{x-2}+\frac{x}{x+3}=\frac{1}{x^2+x-6}# and how do... How do you solve #\frac{x}{x^2-36}+\frac{1}{x-6}=\frac{1}{x+6}#? How do you solve by clearing the denominator of #3/x+2/x^2=4#? How do you solve #2/(x^2+2x+1)-3/(x+1)=4#? How do you solve equations with rational expressions #1/x+2/x=10#? How do you solve for y in #(y+5)/ 2 - y/3 =1#? See all questions in Clearing Denominators in Rational Equations Impact of this question 1440 views around the world You can reuse this answer Creative Commons License