Question

How do you find the center and radius of the circle with this equation: `(x+6)^2 + (y-4)^2 = 36`?

Answer 1

centre = ( -6 , 4 ) and radius = 6

Explanation:

the standard form of the equation of a circle is :

`( x - a )^2 + (y - b )^2 = r^2`

where (a , b ) represents the centre and r the radius.

compare the standard form to `(x + 6 )^2 + (y - 4 )^2 = 36`

`rArr a = - 6, b = 4 and r = sqrt 36 = 6`

`rArr centre = (- 6 , 4 ) and radius = 6`