How do you solve # 2-3[7-2(4-x)]= 2x-1#?

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Answer 1 · 2016-01-08T14:35:37

# x = 3/4 #

this is a multi-step equation.

the first step is to simplify the contents of the 'square bracket'

# 2 -3 ( 7- 8 + 2x ) = 2x - 1 #

now simplify contents of 'new bracket'

#2 - 3 ( - 1 + 2x ) = 2x - 1#

now multiply the bracket by - 3

#2 + 3 - 6x = 2x - 1#

now collect like terms to separate sides of the = sign

#2 + 3 + 1 = 2x + 6x #

#6 = 8x# ( divide both sides by 8 to obtain x )

# 6/8 = (8x)/8 rArr x = 3/4 #