How do you solve $4 (2 x - 1) - 3 = 9 (x - 4)$ $4(2x − 1) − 3 = 9(x − 4)$ ?

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Answer 1 · 2016-01-08T16:57:37

$x = 29$ $color(blue)(x = 29$

$4 (2 x - 1) - 3 = 9 (x - 4)$ $4(2x-1) - 3 = 9(x-4)$

$4 \times (2 x) + 4 \times (- 1) - 3 = 9 \times (x) + 9 \times (- 4)$ $4xx (2x) + 4 xx (-1) - 3 = 9 xx (x) + 9 xx (-4)$

$8 x - 4 - 3 = 9 x - 36$ $8x -4 - 3 = 9 x -36$

$8 x - 7 = 9 x - 36$ $8x -7 = 9 x -36$

$- 7 + 36 = 9 x - 8 x$ $-7 +36 = 9 x -8x$

$- 7 + 36 = x$ $-7 +36 = x$

$x = 29$ $color(blue)(x = 29$

How do you solve 4(2x − 1) − 3 = 9(x − 4)4(2x−1)−3=9(x−4)4(2x − 1) − 3 = 9(x − 4)?