How do you solve #3x-y=9# and #2x+y=1#?

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Answer 1 · 2016-01-08T17:14:35

The solution for the system of equations is
#color(blue)(x=2,y=-3#

#3x-color(blue)(y)=9#......equation #(1)#

#2x +color(blue)(y)=1#......equation #(2)#

Solving by elimination

Adding equations #1# and #2#

#3x-cancelcolor(blue)(y)=9#
#2x +cancelcolor(blue)(y)=1#

#5x =10#

#x=10/5#

#color(blue)(x=2#

Finding #y# from equation #1#

#3x-y=9#

#3 xx 2 -y=9#

#6 -y=9#

#6 -9=y#

#color(blue)(y=-3#