Question

How do you differentiate `f(x)= (3x^2-5x+2)/ (x+1 )` using the quotient rule?

Answer 1

Quotient rule states that `(a/b)'=(a'b-ab')/b^2`

Explanation:

Thus:

`(df(x))/(dx)=((6x-5)(x+1)-(3x^2-5x+2)(1))/(x+1)^2`

`(df(x))/(dx)=(6x^2+x-5-3x^2+5x-2)/(x+1)^2`

`(df(x))/(dx)=(3x^2+6x-7)/(x+1)^2`