Question

How do you solve `9/2x+2=8/x`?

Answer 1

`x=(-2+-2sqrt37)/9`

Explanation:

Multiply through by 2x to remove the fractions.

`9x^2+4x=16`
`9x^2+4x-16=0`
`x=(-4+-sqrt(4^2-4*9*-16))/18`
`x=(-4+-sqrt(592))/18`
`x=(-4+-4sqrt37)/18`
`x=(-2+-2sqrt37)/9`