Question

How do you write `3^(−3/2)` exponential expression in radical form?

Answer 1

`1/sqrt27`

Explanation:

Using the following 'laws of indices'

`a^-m = 1/a^m and a^(m/n) = root(n)(a^m)`

rewrite with a positive index

`3^(-3/2 = 1/3^(3/2 )`

now `3^(3/2) = sqrt(3^3) = sqrt27`

`rArr 3^(-3/2) = 1/sqrt27`