Question

What is the standard form of # y= (x-6)(x+18) #?

Answer 1

`y=x^2+12x-108`

Explanation:

Multiply out the brackets to obtain :

`y=x^2+12x-108`.

This standard form represents a 2nd degree quadratic function (of form `y=ax^2+bx+c`) and its graph would hence be a parabola as shown below

graph{x^2+12x-108 [-304.3, 304, -152.2, 152.2]}