Question

What is the standard form of the equation of a circle with a center (6, 7) and a diameter of 4?

Answer 1

`(x-6)^2+(y-7)^2=2^2`

Explanation:

The standard form of the equation of a circle with centre `(h,k)` and radius `r` is:

`(x-h)^2+(y-k)^2=r^2`

graph{((x-6)^2+(y-7)^2-2^2)((x-6)^2+(y-7)^2-0.025) = 0 [-6.71, 18.6, -1.64, 11.02]}