How do you solve #6 = a/4+2#?

1 Answer
Jan 13, 2016

In order to solve for #a# we need to isolate the #a# term.

Explanation:

#6=a/4+2#

That #a# term is stuck on top of a 4, so we need to get it by itself before we can do anything.

To do that we need to get rid of the +2. How do you do that? by subtracting 2 (or adding -2, which is the same thing)

But since it is an equation (meaning the two sides are equal) we have to do the same thing to both sides:

#6-2=a/4 cancel(+2) cancel(-2)#

so we are left with

#4=a/4#

To get the #a# by itself, we have to eliminate the #1/4#, a division, which we do by multiplying both sides by 4:

#4xx4=a/cancel(4)xxcancel(4)#

leaving

#a=16#