How do you solve #4y - 1/10 = 3y + 4/5#?

1 Answer
Jarni Renz
Jan 14, 2016

#y=(9)/(10)#

Explanation:

  1. Just combine like terms
    #4y-3y=(4)/(5)+(1)/(10)#, find the LCD
    #y=(8+1)/10#
    #y=(9)/10#

Checking:

#4y-1/10=3y+4/5#, plug in the value of #y#
#4(9/10)-1/10=3(9/10)+4/5#, simplify
#36/10-1/10=27/10+4/5#, find the LCD
#35/10=(27+8)/10#
#35/10=35/10#

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